( 3 + 13 2 ) 1 6 ( 13 − 3 2 ) 7 6 + ( 3 + 13 2 ) 7 6 ( 13 − 3 2 ) 1 6 = 13 {\displaystyle {{{\bigg (}{\frac {3+{\sqrt {13}}}{2}}{\bigg )}}^{\frac {1}{6}}{{\bigg (}{\frac {{\sqrt {13}}-3}{2}}{\bigg )}}^{\frac {7}{6}}}+{{\bigg (}{\frac {3+{\sqrt {13}}}{2}}{\bigg )}}^{\frac {7}{6}}{{{\bigg (}{\frac {{\sqrt {13}}-3}{2}}{\bigg )}}^{\frac {1}{6}}}={\sqrt {13}}}
<<School:李煌数学研究院
