( 1 + x ( n − 1 ) ) n = ( x n + x ) ( n − 1 ) + ( 1 + x ( n − 1 ) ) ( n − 1 ) {\displaystyle {\bigg (}1+x^{(n-1)}{\bigg )}^{n}={\bigg (}x^{n}+x{\bigg )}^{(n-1)}+{\bigg (}1+x^{(n-1)}{\bigg )}^{(n-1)}}
School:李煌数学研究院
